2012 AMC 8 Problems/Problem 13
Contents
Problem
Jamar bought some pencils costing more than a penny each at the school bookstore and paid . Sharona bought some of the same pencils and paid . How many more pencils did Sharona buy than Jamar?
Solution 1
We assume that the price of the pencils remains constant. Convert and to cents. Since the price of the pencils is more than one penny, we can find the price of one pencil (in cents) by taking the greatest common divisor of and , which is . Therefore, Jamar bought pencils and Sharona bought pencils. Thus, Sharona bought more pencils than Jamar.
Solution 2
We find the difference between and is .It cost Sharona more to buy pencils. Because the difference between the numbers of peciles they bought must be divided evenly by . So the answer should be or , which gives us the cost of each pencile should be or . Then we find only can be divided evenly by and . So the answer is ---LarryFlora
See Also
2012 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
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All AJHSME/AMC 8 Problems and Solutions |
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